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If a vector A has components A. 0, and Ay -0, then the magnitude of the vector is negative. Select one: True False

User Erben Mo
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2 Answers

5 votes

Answer:

The given statement is false.

Step-by-step explanation:

For a given vector
\overrightarrow{A}=A_(x)\widehat{i}+A_(y)\widehat{j}

The magnitude is given by
|A|=\sqrt{A_(x)^(2)+A_(y)^(2)}

As we can see that the quantity on the right side of equation is always positive since square root of a quantity is always positive thus we conclude that the magnitude of any vector and hence vector A is always positive.

User Daniel Kehoe
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8.2k points
5 votes

Answer:

False

Step-by-step explanation:

The magnitude of any vector is given by,


||A||=√(A_x^2+A_y^2)

The magnitude of anything is never negative. It can be even seen from the formula that the components are squared. A squared value can never be negative. Even if the component is negative the square will be always positive.

So, magnitude of the vector is not negative.

User Milleniumbug
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7.7k points