Answer:
current in series is 1.33 mA
current in parallel is 5.48 mA
Step-by-step explanation:
given data
voltage = 8 V
resistors R1 = 2.5 kilo ohms
resistors R2 = 3.5 kilo ohms
to given data
current flow
solution
current flow in series is express as
current = voltage / resistor
put here all value
current = 8 / (2.5 + 3.5)
current = 8 / 6
current = 1.33 mA
and
current flow in parallel is express as
current = voltage / resistor
put here all value
current = 8 / (1/ (1/2.5 + 1/3.5))
current = 8 / 1.45
current = 5.48 mA