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What is the root of the equation 6x^2-7x-5=0

User Meagen
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1 Answer

4 votes

Answer:

The roots are {-1/2, 5/3}.

Explanation:

6x^2 - 7x - 5 = 0

Use the 'ac' method:

6 * -5 = -30 so we need to find 2 values whose product is -30 and whose sum = the coefficient of x in the given equation ( -7).

-10 and + 3 fit the bill so we write:

6x^2 - 7x - 5 = 0

6x^2 + 3x - 10x - 5 = 0 Factor by grouping:

3x(2x + 1) - 5(2x + 1) = 0

(3x - 5)(2x + 1) = 0

So 3x - 5 = 0 gives x = 5/3, and

2x + 1 = 0 gives x = -1/2.

User Dancow
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