Question

A patient’s urine sample has a density of 1.02 g/ml. If 1250 mL of urine was excreted by the patient in one day, what mass of urine was eliminated?

A) 1.28 kg

B) 1225 g

C) 1275 g

D) 128 g

Answer 1

The mass of urine eliminated is found by multiplying the urine's density (1.02 g/ml) by the volume excreted (1250 mL), resulting in a mass of 1275 g or 1.275 kg. So the correct option is A) 1.28 kg after rounding.

Step-by-step explanation:

The question asks for the mass of urine eliminated by a patient, given a urine sample with a density of 1.02 g/ml and a total volume of urine excretion of 1250 mL in one day. The mass of the urine can be calculated by multiplying the volume of the urine by its density:

Mass = Density × Volume

Mass = 1.02 g/ml × 1250 ml

Mass = 1275 g

Converting the mass to kilograms, as the options provided include kilograms:

Mass in kg = 1275 g × (1 kg / 1000 g)

Mass in kg = 1.275 kg, which is equivalent to option A) 1.28 kg, as it is rounded to two decimal places.

Answer 2

Hey there!

Density of urine = 1.02 g/mL

Volume of urine = 1250 mL

We know density = mass / volume

Thus mass of urine excreted in one day :

mass of urine = density x volume

mass of urine = 1.02 g/mL x 1250mL

mass of urine = 1275 g

Thus the option C is correct