Answer:
42.11 sec
Step-by-step explanation:
In first part : The truck start from the rest that is u = 0 m/sec
Acceleration is given as
![a=1.4m/sec^2](https://img.qammunity.org/2020/formulas/physics/high-school/tw67vfijvyck0yi5i6zqvjdfqraq8h8ob1.png)
It reaches to a velocity of 22 m/sec so v=22 m/sec
Now according to first law of motion
![v=u+at](https://img.qammunity.org/2020/formulas/physics/middle-school/8u69t2dm31jy4f6e8h3i9msisjzkrvuvq4.png)
![22=0+1.4* t](https://img.qammunity.org/2020/formulas/physics/high-school/ywyazxyhp7q4rev3na3tsr2ic5pygtcb1y.png)
![t=15.71sec](https://img.qammunity.org/2020/formulas/physics/high-school/lmw1ft74bt64rmt05661wbme9bhx9xvbcy.png)
In second part : The truck maintain a constant speed for 22 sec
In third part : The truck takes an additional 4.4 sec for stopping
So total time in which the truck is in motion =15.71+22+4.4=42.11 sec