Question

From the balanced molecular equation, write the complete onic and net ionic equation for the following:

(a)K2C2O4 + Ba(OH)2 - > 2KOH + BaC2O2
(b)Pb(NO3)2 + H2SO4 -> 2HNO3 + PbSO4
(c)CaCO3 + H2SO4 = CO2 + CaSO4 + H2O

Answer 1

As given in the problem statement The complete net ionic equations are following

2KOH =k+OH-

H2SO4=H+SO4 2-

Answer 2

Answer : The net ionic equation will be,

(a)
`C_2O_4^(2-)(aq)+Ba^(2+)(aq)\rightarrow BaC_2O_2(s)`

(b)
`Pb^(2+)(aq)+SO_4^(2-)(aq)\rightarrow PbSO_4(s)`

(c)
`CaCO_3(s)+2H^+(aq)\rightarrow CO_2(g)+Ca^(2+)(aq)+H_2O(l)`

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The given balanced ionic equation will be,

`K_2C_2O_4(aq)+Ba(OH)_2(aq)\rightarrow 2KOH(aq)+BaC_2O_2(s)`

The ionic equation in separated aqueous solution will be,

`2K^+(aq)+C_2O_4^(2-)(aq)+Ba^(2+)(aq)+2OH^(-)(aq)\rightarrow BaC_2O_2(s)+2K^+(aq)+2OH^(-)(aq)`

In this equation,
`K^+\text{ and }OH^-` are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

`C_2O_4^(2-)(aq)+Ba^(2+)(aq)\rightarrow BaC_2O_2(s)`

(b) The given balanced ionic equation will be,

`Pb(NO_3)_2(aq)+H_2SO_4(aq)\rightarrow 2HNO_3(aq)+PbSO_4(s)`

The ionic equation in separated aqueous solution will be,

`Pb^(2+)(aq)+2NO_3^(-)(aq)+2H^(+)(aq)+SO_4^(2-)(aq)\rightarrow PbSO_4(s)+2H^+(aq)+2NO_3^(-)(aq)`

In this equation,
`H^+\text{ and }NO_3^-` are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

`Pb^(2+)(aq)+SO_4^(2-)(aq)\rightarrow PbSO_4(s)`

(c) The given balanced ionic equation will be,

`CaCO_3(s)+H_2SO_4(aq)\rightarrow CO_2(g)+CaSO_4(aq)+H_2O(l)`

The ionic equation in separated aqueous solution will be,

`CaCO_3(s)+2H^+(aq)+SO_4^(2-)(aq)\rightarrow CO_2(g)+Ca^(2+)(aq)+SO_4^(2-)(aq)+H_2O(l)`

In this equation,
`SO_4^(2-)` is the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.The net ionic equation will be,

`CaCO_3(s)+2H^+(aq)\rightarrow CO_2(g)+Ca^(2+)(aq)+H_2O(l)`