Question

A small beaker is 1/3 filled with salt water. Another beaker, which has five times the capacity of the small beaker, is 1/4 filled with fresh water. After dumping all of the salt water from the small beaker into the large beaker, to what fraction of its capacity will the large beaker be filled? A. 7/12B. 7/24C. 17/24D. 17/60E. 19/60

Answer 1

The large beaker is 19/60 filled with mixed of salt and fresh water ⇒ E

Explanation:

* Lets explain the information to solve the problem

- A small beaker is 1/3 filled with salt water

- A large beaker has five times the capacity of the small beaker

- The large beaker is 1/4 filled with fresh water

- All of the salt water is dumping from the small beaker into the

large beaker

- We need to find to what fraction of its capacity the large beaker

will be filled

* At first lets find the the small beaker is how many times the

large beaker

∵ The capacity of large beaker is 5 times the capacity of the

small beaker

∴ The capacity of the small beaker = 1/5 the capacity of the

large beaker

- Now lets calculate the fraction of the quantity of salt water in

the large beaker

∵ The small beaker is 1/3 filled with salt water

∴ The fraction of the salt water in the large beaker = 1/3 × 1/5 = 1/15

- Lets add the quantities of the salt water and the fresh water

∵ The large beaker is 1/4 filled with fresh water

∴ The the fraction of the two quantities =
`(1)/(4)+(1)/(15)`

∵ The lowest common factor of 4 and 15 is 60

∴
`(1(15))/(60)+(1(4))/(60)`

∴
`(15)/(60)+(4)/(60)` =
`(19)/(60)`

∴ The large beaker is 19/60 filled with mixed of salt and fresh water