Question

Randal plays a game at the fair. He wins a prize if he throws a bean bag and knocks over a stuffed clown. Each game costs $1 to play and $2 for each bean bag. Write a rule for the cost of a game. Write ordered pairs for the cost of the game when Randal plays with 1, 2, 3, and 4 bean bags. A. y = 2 + x (1, 1), (2, 3), (3, 5), (4, 7) B. y = 2 + x (1, 2), (2, 4), (3, 6), (4, 8) C.y = 1 + 2x (1, 2), (2, 4), (3, 6), (4, 8) D. y = 1 + 2x (1, 3), (2, 5), (3, 7), (4, 9)

Answer 1

The correct option is D.

Explanation:

It is given that each game costs $1 to play and $2 for each bean bag.

Let x be the number of bean bags and y be the total cost of the game.

Initial cost = $1

Variable cost = $2

The cost function is

Total cost = Initial cost + (cost of a bean bag × Number of bean bags)

`y=1+2x`

The rule for the cost of a game is y=1+2x.

At x=1,

`y=1+2(1)=1+2=3`

At x=2,

`y=1+2(2)=1+4=5`

At x=3,

`y=1+2(3)=1+6=7`

At x=4,

`y=1+2(4)=1+8=9`

The ordered pairs for the cost of the game when Randal plays with 1, 2, 3, and 4 bean bags, are (1, 3), (2, 5), (3, 7), (4, 9).

Therefore the correct option is D.

Answer 2

D
`y=1+2x`

(1,3),(2,5),(3,7),(4,9)

Explanation:

We are given that Randal plays a game at the fair

Cost of a game=$1

Cost of a bean bag=$2

Randal plays with 1,2,3 and 4 bean bag

We have to find rule for the cost of game and ordered pair for the cost of the game when Randal plays with given bean bags

Let x be the number of bean and y be the total cost of a game

Then , according to question

Total cost of bean bag=2x

Total cost of a game is given by

`y=1+2x`

Substitute x=1

Then , we get
`y=1+2(1)=3`

Substitute x=2, then we get

`y=1+2(2)=1+4=5`

Substitute x=3 ,then we get

`y=1+2(3)=1+6=7`

Substitute x=4

Then ,we get

`y=1+2(4)=1+8=9`

Hence, Option D is true.

Answer:D
`y=1+2x`

(1,3),(2,5),(3,7),(4,9)