Question

An aircraft, traveling northward, lands on a runway with a speed of 77 m/s. Once it touches down, it slows to 6.3 m/s over 705 m of runway. What is the average acceleration (magnitude and direction) of the plane during landing (in m/s2)

Answer 1

magnitude

`a = 4.18 m/s^2`

Direction

Opposite to the velocity of aircraft

Step-by-step explanation:

As we know that the initial speed of the aircraft when it land on the ground is

`v_i = 77 m/s`

now the final speed of the aircraft when it covers 705 m on runway is given as

`v_f = 6.3 m/s`

so here we know that

`v_f^2 - v_i^2 = 2 a d`

so now we can say that

`6.3^2 - 77^2 = 2ad`

`6.3^2 - 77^2 = 2(a)(705)`

`a = -4.18 m/s^2`