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In the stimulated emission for a certain helium/neon laser, the energy difference is 1.96 eV. What is the wavelength of light emitted by this laser?

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Answer:

633 nm

Step-by-step explanation:

E = Energy difference = 1.96 eV

c = Speed of light = 3×10⁸ m/s

h = Planck's constant = 6.626×10⁻³⁴ J/s

Converting eV to J

1 eV = 1.6×10⁻¹⁹ J

1.96 eV = 1.96×1.6×10⁻¹⁹ Joule = 3.136×10⁻¹⁹ Joule

Photon energy equation


E=(hc)/(\lambda)\\\Rightarrow \lambda=(hc)/(E)\\\Rightarrow \lambda=(6.626* 10^(-34)* 3* 10^8)/(3.136* 10^(-19))\\\Rightarrow \lambda=6.33* 10^(-7)\ m

∴ Wavelength of light emitted by this laser is 633 nm

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