Question

Using the Bohr model, find the wavelength in nanometers of the radiation emitted by a hydrogen atom, when it makes a transition from the n = 9 state to the n = 1 state.

Answer 1

0.92265 nm

Step-by-step explanation:

We have given electron transits from state 1 to state 9

So
`n_1=1` and
`n_2=9`

Now according to Bohr's rule
`(1)/(\lambda )=R\left ( (1)/(n_1^2)-(1)/(n_2^2)\right )` here R is Rydberg constant which value is 10973731.6
`m^{-1`

So
`(1)/(\lambda )=10973731.6\left ( (1)/(1^2)-(1)/(9^2)\right )`

`(1)/(\lambda )=10838253.43m^(-1)`

`\lambda =9.2265* 10^(-8)m=0.92265nm`