Question

Determine the percent water in CuSO4.5 H2O to three significant figures.

Answer 1

`\%\;of \;water = 36.08\%`

Step-by-step explanation:

Molecular mass of
`CuSO_4.5H_2O = 249.72\;g/mol`

Molecular mass of
`H_2O = 18.02\;g/mol`

In
`CuSO_4.5H_2O`, 1 mole of compound has 5 moles of
`H_2O`.

Mass of 5 moles of
`H_2O = No.\; of\;mole\;of\;water *\;molecular\;mass\;of\;water`

Mass of 5 moles of
`H_2O = 5* 18.02 = 90.10\;g/mol`

`\%\;of \;water=(Mass\;of\;water)/(Tolat\;mass\;of\;CuSO_4)`

`\%\;of \;water = (90.10)/(249.72)* 100= 36.08\%`