Question

A child sits 1.6 m from the center of a merry go round that makes one complete revolution in 4.7 s. What is his angular acceleration?

Answer 1

Answer: angular acceleration =
`2.86\ rad/sec^(2)`

Given:

Distance from center of axis = 1.6 m

Time taken to complete one revolution = 4.7 sec

Therefore, we can evaluate the angular acceleration using the following formula:

`\alpha = r* \omega^(2)`

`\alpha = r* ((2\pi)/(T))^(2)`

`\alpha = 1.6* ((2*3.14)/(4.7))^(2)`

`\alpha` =
`2.86\ rad/sec^(2)`