Question

An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1 travels up north while m2 travels at a downward angle of θ caused by the collision. In this perfectly elastic collision, find: a) v1'

b) v2'
c) θ

Answer 1

`v`Θ

`v^(`Θ

Θ =
`tan^(-1)((v^(`

Step-by-step explanation:

Applying the law of conservation of momentum, we have:

Δ
`p_(x = 0)`

`p_(x) = p`

`m_(1)v_(1) = m_(2)v`Θ (Equation 1)

Δ
`p_(y) = 0`

`p_(y) = p`

`0 = m_(1) v`Θ (Equation 2)

From Equation 1:

`v`Θ

From Equation 2:

`m_(2) v`sinΘ =
`m_(1) v_(1)`

`v`

Replacing Equation 3 in Equation 4:

`v`

`v`

`v`Θ (Equation 5)

And we found Θ from the Equation 5:

tanΘ=
`(v`

Θ=
`tan^(-1)((v`