Answer:
![54%](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v0boicibplyvut5oxdjmp8p4121n4hxffk.png)
Explanation:
Given is a frequency table showing the students' scores on a recent math test.
Score Frequency
41-50 1
51-60 2
61-70 8
71-80 12
81-90 20
91-100 7
We have to find the percentage of the students scored at least 81
on the test
From the frequency table we find that 20 students gained 81 to 90 and 7 students from 91 to 100
No of studence who scored atleast 80
![= 20+7 =27](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gtavfhy4vzcslpmn8sxl0z9gf3z5lwb8og.png)
Total frequency =
![50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pn3hqg7e3dzo61faoa5ac4xrbkiwxi7agh.png)
Hence percentage of the students scored at least 81
on the test=
![(27)/(50) (100) = 54%](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qkyojrhozss7zn5v3fr5wje1mntki1r3z0.png)
Answer is
![54%](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v0boicibplyvut5oxdjmp8p4121n4hxffk.png)