Answer:
Option C
y=5x-11
Explanation:
We first find the gradient,m, of the line that passes through the points (3,4) and (2,-1)
Let
x=3
y=4
![x_1=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/2z2a6dpeh93adom8p8de4tzg0o6ldem8v8.png)
![y_1=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tejy291pczw1uyp57bin6lvht5rlndcz4x.png)
![m=(y - y_1)/(x - x_1)](https://img.qammunity.org/2020/formulas/mathematics/college/z05dnknjmmkbpua092y3pgmu07xkc6wokw.png)
By substitution,
![m=(4-(-1))/(3-2)=(4 + 1)/(1) = (5)/(1)=5](https://img.qammunity.org/2020/formulas/mathematics/college/ufvlyf97djnud7awqdpjbgpjn4dwxz6jnj.png)
Putting that m=5, x=3 and y=4 into the general equation,
y=mx+c
This implies that
4=5(3)+c
4=15+c
4-15=c
c=-11
The equation of the line is given as
y=mx+c
where m=5 and c=-11
Hence y=5x-11