Question

Please help. It due in less than an hour.

Answer 1

bearing in mind that parallel lines have exactly the same slope, hmmmm what's the slope of the equation above anyway?

`\bf y=\stackrel{\stackrel{m}{\downarrow }}{-4}x+12\qquad \impliedby \begin{array} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}`

so, we're really looking for the equation of a line whose slope is -4 and runs through (5,-13),

`\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-13})~\hspace{10em} \stackrel{slope}{m}\implies -4 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-13)}=\stackrel{m}{-4}(x-\stackrel{x_1}{5}) \\\\\\ y+13=-4x+20\implies y=-4x+7`