Question

If the product of zeroes of polynomial ax^2-6x-6 is 4, find the value of 'a'

Answer 1

a = - 1.5

Explanation:

given a quadratic equation in standard form

ax² + bx + c = 0

then the product of the roots =
`(c)/(a)`

ax² - 6x - 6 = 0 ← in standard form

with c = - 6

then

`(-6)/(a)` = 4 ( multiply both sides by a )

- 6 = 4a ( divide both sides by 4 )

`(-6)/(4)` =
`(-3)/(2)` = - 1.5 = a