Question

How many atoms are in the product of the following reaction? 2KClO3 ⇋ 2KCl + 3O2 6 8 5 10

Answer 1

Answer: The answer is 10.

Answer 2

10 is the answer.

Step-by-step explanation:

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient × subscript

For example
`5 Ca_1 Cl_2` contains

5 × 1 = 5 , Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
`3Ca_3 (P_1 O_4 )_2` we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So 3 × 3 = 9, Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

Product side contains
`2KCl+3O_2`

2, K

2, Cl

6, O

So totally 2 + 2 + 6 = 10 atoms present on the product side