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Sabrina rode on a Ferris wheel at the state fair. The radius of the Ferris wheel was 150 feet. What is the approximate distance Sabrina traveled in one revolution of the Ferris wheel

User ManiAm
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Final answer:

Sabrina traveled approximately 942 feet in one revolution of the Ferris wheel with a radius of 150 feet.

Step-by-step explanation:

The distance Sabrina travels in one revolution of the Ferris wheel can be calculated using the formula for the circumference of a circle, which is C = 2πr, where r is the radius of the circle. In this case, the radius of the Ferris wheel is 150 feet. Plugging in the value for r, we get C = 2π(150) = 300π feet. To approximate this value, we can use the approximation π ≈ 3.14. So, the approximate distance Sabrina traveled in one revolution of the Ferris wheel is 300(3.14) ≈ 942 feet.

User Arkku
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