184k views
1 vote
The LCM of two prime numbers x and y (x>y) is 161. Find the remainder when x is divided by y.

Answer

1 Answer

5 votes

Answer:

2

Explanation:

Since LCM of x and y is 161, this means x and y are factors of 161. The factors of 161 are:

1 , 7, 23, 161

Since x and y are prime numbers and it is given that x > y, the only possible solution for x and y is:

x = 23

y = 7

We have to find what is the remainder when x=23 is divided by y=7. We know that 7 times 3 = 21. This means, when 23 is divided by 7, the quotient is 3 and the remainder is 2.

Therefore, the answer to this question is 2.

User Alex Ushakov
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories