Question

Not sure where to begin with this

Answer 1

The third option:

The object's acceleration is 0 m/
`s^2` for the first 2 seconds because the velocity is not changing. Then, the object undergoes a positive constant acceleration because the slope is positive and constant.

Explanation:

First. I should note that the y-axis of this graph shows the velocity.

To see the acceleration, we should look at the slope of the velocity.

From [0,2] there is a slope of 0, this means that the acceleration is 0

From [2,4] there is a slope of
`(1)/(2)`, which means that the acceleration is
`(1)/(2)` m/
`s^2` . This is a positive constant acceleration.