Question

3H2 + N2 —> 2NH3 .

How many molecules (not moles) of NH3 are produced from 6.33x10^-4 g of H2?

Answer 1

`\boxed{1.26 * 10^(20) \text{ molecules NH}_(3)}`

Step-by-step explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

M_r: 2.016 17.03

3H₂ + N₂ ⟶ 2NH₃

m/g: 6.33 × 10⁻⁴

2. Calculate the moles of H₂

`\text{Moles of H}_(2) = 6.33 * 10^(-4)\text{ g H}_(2) * \frac{\text{1 mol H}_(2)}{\text{2.016 g H}_(2)} = 3.140 * 10^(-4) \text{ mol H}_(2)`

3. Calculate the moles of NH₃

The molar ratio is 2 mol NH₃/3 mol H₂.

`\text{Moles of NH}_(3) = 3.140 * 10^(-4) \text{ mol H}_(2) * \frac{\text{2 mol NH}_(3)}{\text{3 mol H}_(2)} = 2.093 * 10^(-4)\text{ mol NH}_(3)`

4. Calculate the molecules of NH₃

There are 6.022 × 10²³ molecules of NH₃/1 mol NH₃.

`\text{Molecules of NH}_(3) = 2.093 * 10^(-4)\text{ mol NH}_(3) * \frac{6.022 * 10^(23)\text{ molecules NH}_(3)}{\text{1 mol NH}_(3)}\\= 1.26 * 10^(20)\text{ molecules NH}_(3)\\\text{The reaction produces } \boxed{\mathbf{1.26 * 10^(20)} \textbf{ molecules NH}_(3)}`