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21. Solve for ‘x.
11
13
21
a. 5
b. 11
c. 12

21. Solve for ‘x. 11 13 21 a. 5 b. 11 c. 12-example-1

1 Answer

2 votes

Answer:

c. 12

Explanation:

Deduct 11 from 21 to get 10, then split it in half, to get 5 as your two bases for the right triangles. Now, according to the Pythagorean Theorem, a² + b² = c², in this case, since the hypotenuse, c, is already defined, use Subtraction to find the other leg:


25 = 5^2 \\ 169 = {13}^(2)

25 + b² = 169

-25 - 25

______________

√b² = √144

b = 12

When we are talking about lengths, we want the NON-NEGATIVE root.

I am joyous to assist you anytime.

User Volodymyr Baydalka
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