Question

Unpolarized light passes through two polarizers; the axis of one is vertical and that of the other is at 54.0 o to the vertical. What is the ratio of the transmitted light intensity to the original light intensity?

Answer 1

0.3455

Step-by-step explanation:

Using Malus law as:

`I=I_0* cos^2\ \theta`

Where,

`I=` is the intensity of the transmitted light

`I_0` is the intensity of the incident light

`\theta` is the angle between the polarizer.

Given that:

`\theta=54.0^0`

To find the ratio of the transmitted light intensity to the original light intensity which is
`\frac {I}{I_0}`

So,

`\frac {I}{I_0}=cos^2\ 54^0=0.3455`