Question

Calculate the force of attraction between a K+ and an O2- ion the centers of which are seperared by a distance of 1.5 nm.

Answer 1

`F=2.04* 10^(-10) N`

Step-by-step explanation:

Given that

`q_1=1* 1.6* 10^(-19)`

`q_2=2* 1.6* 10^(-19)`

r= 1.5 nm

We know that force between two charge given as follows

`F=K(q_1q_2)/(r^2)`

Where K is the constant

Noe by putting the values

`q_1* q_2=2* 1.6*1.6* 10^(-38)`

`F=8.98* 10^9 * (5.12* 10^(-38))/(\left ( 1.5*10^(-9) \right )^2)`

`F=2.04* 10^(-10) N`