Question

A 2X2 matrix M is given by (ab) lcd) Given that a = 19, b = 24 and c = 38, what is the value of d such that the matrix Mis singular. Give your answer to the nearest integer.

Answer 1

Value of d is:

48

Explanation:

We are given a matrix M as:

M=
`\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]`

We are given that:

a=19, b=24 and c=38

We have to find the value of d so that M is singular

i.e. determinant of M=0

i.e. ad-bc=0

i.e. 19d-24×38=0

i.e. 19d=24×38

i.e. d=
`(24* 38)/(19)`

i.e. d=48

Hence, Value of d is:

48