Question

A cylinder which is in a horizontal position contains an unknown noble gas at 52600 Pa and is sealed with a massless piston. The piston is slowly, isobarically moved inward 0.150 m, while 18600 J of heat is removed from the gas. If the piston has a radius of 0.305 m, calculate the change in internal energy Δ???? of the system. Δ???? = _______J

Answer 1

Answer:-16.3 kJ

Step-by-step explanation:

Given

Pressure inside Cylinder=52,600 Pa

Piston Moved Slowly inwards 0.15 m

Area of piston(A)
`=(\pi )/(4)d^2`

`A=0.2922 m^2`

Change in volume=A\Delta L[/tex]

`\Delta V=0.292* 0.15=0.04384 m^3`

Heat removal=18,600 J

From First Law of thermodynamics

`\Delta U=Q-W`

`W=P\Delta V`

`W=52600* 0.04384=-2.3061 kJ`

as volume is decreasing

Q=-18.6 kJ

`\Delta U=-18.6+2.3061`

`\Delta U=-16.29 \approx 16.3 kJ`