Question

Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K

Substance ΔG°f (kJ/mol) at 298 K

SnO( s) ?

SnO 2( s) –515.8

Answer 1

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

Step-by-step explanation:

`Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_(f)^(o) = 12.0 kJ`

`\Delta G_(f,SnO_2)^(o)= -515.8kJ/mol`

`\Delta G_(f,Sn)^(o)= 0 kJ/mol`

`\Delta G_(f,SnO)^(o)=?`

`\Delta G_(f)^(o)=\sum ((\Delta G_(f)^(o))_ {products})-\sum ((\Delta G_(f)^(o))_ {reactants})`

`12.0 kJ=(2 mol* \Delta G_(f,SnO)^(o))-(1mol* 0 kJ/mol+1 mol* -515.8 kJ/mol)`

`\Delta G_(f,SnO)^(o)=-251.9 kJ/mol`

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.