Question

Approximate the field by treating the disk as a +6.1 C point charge at a distance of 21 cm Answer in units of N/C.

Answer 1

Electric field,
`E=1.24* 10^(12)\ N/C`

Step-by-step explanation:

It is given that,

Charge, Q = +6.1 C

Distance, r = 21 cm = 0.21 m

We need to find the electric field. It is given by :

`E=k(Q)/(r^2)`

`E=9* 10^9* (6.1)/((0.21)^2)`

`E=1.24* 10^(12)\ N/C`

So, the electric field at this distance is
`1.24* 10^(12)\ N/C`. Hence, this is the required solution.