Answer:
![y=(-3)/(5)x+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m8f3zqf4vlh0p7xkussutv5ncufcwkp6n0.png)
I don't see this in any of your choices.
Please be sure the problem and choices are as you want them to be seen by others. Thanks kindly.
I do hope my answer is helpful.
Explanation:
![3x+5y=15](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3zlsw8bqu0lvp4t2k48td9miqcgytivc4j.png)
We want to get the term that contains
by itself.
This means we want to get
by itself first.
To do this I need to get rid of the plus
on that side.
I will do the inverse operation of that; I will subtract 3x on both sides.
![3x+5y=15](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3zlsw8bqu0lvp4t2k48td9miqcgytivc4j.png)
-3x -3x
![5y=15-3x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hsruanziusklyiwcvcrmj3q0ur5a45cf8j.png)
![5y=+15-3x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3sgl5ylsvuqpaufbaalm2basseu9x0femb.png)
since addition is commutative.
Now we have the 5y term by itself. We want the factor y in 5y by itself.
To undo multiplication you must divide. We will divide both sides by 5:
![5y=-3x+15](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wm83bjxpkc8yfcy2biycotdtjonnixlcxn.png)
------------------------------
5
![(5y)/(5)=(-3x+15)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pddn9zu9fx3gdjtii5bwfi0zarartun5wx.png)
![y=(-3x)/(5)+(15)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v3iupm7yjv6wonnkbiw7igcr2zl7g788dr.png)
![y=(-3)/(5)x+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m8f3zqf4vlh0p7xkussutv5ncufcwkp6n0.png)