Question

The rectangular coils in a 345-turn generator are 12 cm by 12 cm. Part A

What is the maximum emf produced by this generator when it rotates with an angular speed of 505 rpm in a magnetic field of 0.45 T ? Express your answer using two significant figures.

Answer 1

118.166 volt

Step-by-step explanation:

We have given number of turns N =345

Sides of the rectangular coils is 12 cm =0.12 m

So area A =0.12×0.12=0.0144
`m^2`

Magnetic field B =0.45 T

Angular speed =505 rpm

Speed in rad/sec
`\omega =(2\pi N)/(60)=(2* 3.14* 505)/(60)=52.8566rad/sec`

The emf is given by
`E=NAB\omega SIN\omega t`

For maximum emf sinwt =1

So
`E=345* 0.0144* 0.45* 52.8566=118.166volt`