Question

Calculate the magnitude of the force on an electron moving at 1.1x10^6 m/s at an angle of 5.8 degrees to a magnetic field of 0.6 Tesla. Give your answer in Newtons.

Answer 1

The force on electron is
`106.715* 10^(-16)`Newtons

Step-by-step explanation:

The force on a moving charge in a magnetic field is given by

`\overrightarrow{F}=q\overrightarrow{v}* \overrightarrow{B}\\\\=|F|=q|v||B|sin(\theta )`

Applying the given values we get

`F=1.6* 10^(-19)* 1.1* 10^(6)* 0.6* sin(5.8)\\\\\therefore F=106.715* 10^(-16)Newtons`