Question

To sterilize a 48.0-g glass baby bottle, we must raise its temperature from 16.0°C to 94.0°C. How much heat transfer is required?

Answer 1

3144.96 J

Step-by-step explanation:

Heat transfer is,

`q=mc\Delta t`

As we know that the specific heat of the glass is,

`c=0.840J/g^(\circ)C`

Given that the mass of bottle is 48 g.

And the initial temperature is 16°C and the final temperature is 94°C.

Therefore,

`q=48* 0.840(94^(\circ)-16^(\circ))\\q=48* 0.840* 78^(\circ)\\q=3144.96 J`