Question

Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag
Avogadro's number: 6.02 x 1023

Answer 1

Answer : The number of silver atoms produced will be
`39.66* 10^(23)`

Explanation : Given,

Number of atoms of copper =
`19.83* 10^(23)`

The given balanced chemical reaction,

`Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag`

From the balanced chemical reaction we conclude that,

As,
`6.02* 10^(23)` number of copper atoms react to give
`2* 6.02* 10^(23)` number of silver atoms.

So,
`19.83* 10^(23)` number of copper atoms react to give
`2* (6.02* 10^(23))/(6.02* 10^(23))* 19.83* 10^(23)=39.66* 10^(23)` number of silver atoms.

Therefore, the number of silver atoms produced will be
`39.66* 10^(23)`