Question

A fidget spinner experiences a constant torque of 1.4 N.m. If the spinner is initially at rest, what is its angular momentum 2.0 s later?

Answer 1

`2.8N-msec`

Step-by-step explanation:

We have given torque
`\tau =1.4N-m`

Initial time
`t_1=0\ sec`

Final time
`t_2=2\ sec`

There is relation between angular momentum and torque

that is
`(dL)/(dt)=\tau`

`dL=\tau dt`

`\int dL=\tau \oint_(t_1)^(t_2)dt`

`L=\tau (t_1-t_2)=1.4* (2-0)=2.8N-msec`