Question

A solenoid contains 705 coils of very thin wire evenly wrapped over a length of 15.5 cm. Each coil is 2.50 cm in diameter. If this solenoid carries a current of 6.5 A, what is the magnetic field at its center?

Answer 1

The magnetic field at its center is 0.037 T.

Step-by-step explanation:

Given that,

Number of coil = 705

Length = 15.5 cm

Diameter = 2.50 cm

Current = 6.5 A

We need to calculate the magnetic field at its center of solenoid

Using formula of magnetic field

`B= (\mu NI)/(L)`

Where, I = current

L = length

N = number of coil

Put the value into the formula

`B=(4\pi*10^(-7)*705*6.5)/(15.5*10^(-2))`

`B=0.037\ T`

Hence, The magnetic field at its center is 0.037 T.