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Suppose you want to operate an ideal refrigerator with a cold temperature of −11°C, and you would like it to have a coefficient of performance of 6.30. What is the hot reservoir temperature (in °C) for such a refrigerator?

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Answer:

The temperature of hot reservoir is 30.58 degrees Celsius.

Step-by-step explanation:

It is given that,

Temperature of the cold reservoir,
T_c=-11^(\circ)C=-11+273=262\ K

Coefficient of performance,
CP=6.3

We need to find the temperature of hot reservoir for such a refrigerator. The coefficient of performance is given by :


CP=(T_c)/(T_h-T_c)


T_h is the temperature of hot reservoir


T_h-T_c=(T_c)/(CP)


T_h=(T_c)/(CP)+T_c


T_h=(262)/(6.3)+262


T_h=303.58\ K

or


T_h=30.58^(\circ)C

So, the temperature of hot reservoir is 30.58 degrees Celsius. Hence, this is the required solution.

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