Question

Late on an autumn day, the relative humidity is 44.0% and the temperature is 20.0°C. What will the relative humidity be that evening when the temperature has dropped to 10.0°C, assuming constant water vapor density?

Answer 1

humidity is 80.95 %

Step-by-step explanation:

given data

humidity = 44% = 0.44

temperature = 20.0°C

temperature = 10.0°C

to find out

relative humidity

solution

we know humidity formula that is

humidity =
`(vapor density)/(saturated vapor density)` × 100 ...................1

so here at 20.0°C

vapor density is

vapor density = humidity × saturated vapor density

here

saturated vapor density at 20.0°C is 17.3 gm/m³

so

vapor density = 0.44 × 17.3

vapor density = 7.61

and

for 10.0°C

saturated vapor density at 10.0°C is 9.4 gm/m³

so from equation 1

humidity =
`(vapor density)/(saturated vapor density)` × 100

humidity =
`(7.61)/(9.4)` × 100

humidity = 80.95 %