Question

What mass of oxygen will react with 25.0 g of CH3OH? 0/1 point BOO O 2CH3OH + 302 - 2002 + 4H20 16.65 18.75 37.55 8.325 O in O N ! Incorrect

Answer 1

Answer: 37.44 g

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP, contains avogadro's number
`6.023* 10^(23)` of particles and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

`\text{Number of moles of methanol}=(25g)/(32g/mol)=0.78moles`

`2CH_3OH+3O_2\rightarrow 2CO_2+4H_2O`

According to stoichiometry:

2 moles of methanol react with 3 moles of oxygen

Thus 0.78 moles of methanol will react with=
`(3)/(2)* 0.78=1.17` moles of oxygen

Mass of oxygen =
`moles* {\text {molar mass}}=1.17* 32=37.44g`

Thus 37.44 g of oxygen will react with 25.0 g of
`CH_3OH`