Choice A is the correct answer. Nice work.
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One way to see this is to use the rule
![\sqrt[n]{x^m} = x^(m/n)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gmc3diqppzb1i8b9g3eqy2ctpqtwlddr3z.png)
and that leads to
![\sqrt[4]{x^(10)} = x^(10/4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tr5bl8nw7um1ipjjel78epcy1d4iq575l6.png)
which means we'll divide the 10 and 4 to get 10/4 = 2.5 = 2 remainder 2
The "2 remainder 2" part is all we care about really. The whole part 2 forms the exponent over the first x shown in choice A, while the "remainder 2" portion is the exponent over the x inside the root.
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Here's another example:
![\sqrt[4]{x^(27)} = x^(27/4) = x^6\sqrt[4]{x^3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2d92yafjzbtfzs6txycttn7uehaaflzdxs.png)
Note how 27/4 = 6 remainder 3. We see that the whole part 6 is the first exponent of the result while 3 is the second exponent.