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On a winter day with a temperature of -10°C, 500g of snow (water ice) is brought inside where the temperature is 18 °C. The snow warms, then melts to water, and then warms to room temperature. What is the total amount of heat energy absorbed by the snow in this process

1 Answer

4 votes

Answer:

215300 J

Step-by-step explanation:

Heat absorbed in raising the temperature of ice by 10 ° C to 0°C

mass x specific heat x rise in temp

= .5 x 2100 x 10

=10500 J.

Heat required to melt the ice at 0°C

= mass x latent heat

= .5 x 334000

= 167000 J

Heat required to raise the temperature of water from 0 to 10 degree

.5 x 4200 x 18

= 37800 J

Total heat required

= 37800 + 167000 + 10500

= 215300 J

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