Answer:
215300 J
Step-by-step explanation:
Heat absorbed in raising the temperature of ice by 10 ° C to 0°C
mass x specific heat x rise in temp
= .5 x 2100 x 10
=10500 J.
Heat required to melt the ice at 0°C
= mass x latent heat
= .5 x 334000
= 167000 J
Heat required to raise the temperature of water from 0 to 10 degree
.5 x 4200 x 18
= 37800 J
Total heat required
= 37800 + 167000 + 10500
= 215300 J