Question

Create a program in C which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number will represent the ON/OFF state of a toggle switch.

Write a function(s) that will Print 2 lines based on number input by user: Line 1- print Switch numbers (1-7); Line 2- print the "ON" or "OFF" state for each switch (assume 1 = ON).

Answer 1

// here is code in C.

#include <stdio.h>

void fun(int num)

{ // array to store binary representation of input number

int b[7];

int i,j;

// convert the number into binary

for(i=0; num>0; i++)

{

b[i]=num%2;

num= num/2;

}

// print the switch number and their status

printf("Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \\");

printf("Switch status:");

// if bit is 1 print "ON" else "OFF"

for(j=6;j>=0;j--)

{

if(b[j]==1)

printf("\t ON");

else

printf("\t OFF");

}

}

// driver function

void main()

{

int n;

printf("enter the number between 1-100 only:");

// read a decimal number

scanf("%d",&n);

// validate the input between 1 to 100 only

while(n<1 ||n>100)

{

printf("wrong input:");

printf("\\ enter again :");

scanf("%d",&n);

}

// printf( "input number is: %d \\",n);

// call the function

fun(n);

}

Step-by-step explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-1

wrong input:

enter again :104

wrong input:

enter again :68

Switch number: 1 2 3 4 5 6 7

Switch status: ON OFF OFF OFF ON OFF OFF