Question

A small region of space in the shape of a cube of side 1 mm, contains 10.0 J of energy in the form of an electric field. Calculate the magnitude of the electric field (Vm-1)

Answer 1

electric field is 4.75 ×
`10^(10)` V/m

Step-by-step explanation:

given data

cube of side = 1 mm

energy = 10 J

to find out

magnitude of the electric field

solution

to find electric field

we will apply here energy formula that is

energy = 1/2 × ∈ × E² × volume ...............1

here we know ∈ = 8.85 ×
`10^(-12)`

so put all value to get E electric field

energy = 1/2 × ∈ × E² × volume

10 = 1/2 × 8.85 ×
`10^(-12)` × E² × (1/1000)³

solve it and get E

E² = 2× 10 / 8.85 ×
`10^(-12)` × (1/1000)³

E = 4.75 ×
`10^(10)`

so electric field is 4.75 ×
`10^(10)` V/m