Question

If the equation of a circle is (x - 2)2+(-6)2 = 4, the center is point (2,6).

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Answer 1

If you meant to write (x-2)^2 + (y-6)^2 = 4, then the center is (2,6). The statement would be true.

This is because the general form (x-h)^2 + (y-k)^2 = r^2 describes a circle centered at (h,k) with radius r. In this case, h = 2, k = 6, r = 2. Note how r^2 = 4 so r^2 = 2^2 leads to r = 2.