Question

E total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?

Answer 1

KE= 687.21 BTU

Step-by-step explanation:

Given that

Mass of car = 2500 lbm

We know that 1 lb=0.45 kg

So the mass of car m =1133.98 kg

Velocity of car= 80 mph

We know that 1 mph =0.44 m/s

So velocity of car = 35.76 m/s

As we know that kinetic energy (KE) is given as follows

`KE=(1)/(2)mv^2`

Now by putting the values

`KE=(1)/(2)* 1133.98* 35.76^2`

KE=725.05 KJ

We know that 1 KJ = 0.94 BTU

So KE= 687.21 BTU