Question

An LC circuit has an inductance of 14 mH and a capacitance of 3.4 mF. If the charge amplitude is 52 mC, what is the current amplitude?

Answer 1

current amplitude is 31.03 A

Step-by-step explanation:

given data

inductance L =14 mH

capacitance C = 3.4 mF = 3.4

charge amplitude q = 52 mC

to find out

current amplitude

solution

we will apply here formula for current that is

current = v
`√(L/C)` .............1

here v will calculate first

so we know q = c × v

put here value to find v

v = q/c = 52 ×
`10^(-3)` / 3.4 ×
`10^(-3)`

v = 15.29 V

so from equation 1

current = 15.29
`\sqrt{14×[tex]10^(-3)` / 3.4 ×
`10^(-3)` }[/tex]

current = 31.03 A

so current amplitude is 31.03 A