Question

What is the volume of 120 x 1022 molecules of nitric oxide gas, NO, at si B) 2.24L C) 0.0199 L D) 5.02 A) 1120 L

Answer 1

Answer: 44.8 L

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's number}}=(120* 10^(22))/(6.023* 10^(23))=2moles`

1 mole of
`NO` occupies volume = 22.4L at STP

Thus 2 moles of magnesium react with=
`(22.4)/(1)* 2=44.8L`

Thus the volume of
`120* 10^(22)` molecules of nitric oxide gas is 44.8 L.