Question

The gravitational acceleration on the Earth's surface is ce of a plan et with the same size, but twice the mass? it be on the A. 16 fect B. 32 fect/second/second C. 64 f D. 128 foet/second second E. 8 feet 18-

Answer 1

Step-by-step explanation:

The acceleration due to gravity is on Earth is given by :

`g_e=(GM_e)/(R^2)`..............(1)

Where

M is the mass of Earth

R is the radius of Earth

G is the universal gravitational constant

`g_e=32\ ft/s^2`

The formula for acceleration due to gravity on planet is given by :

`g_p=(GM_p)/(R_p^2)`..............(2)

Since,
`M_p=2M_e`

From equation (1) and (2) :

`(g_p)/(g_e)=(M_p)/(M_e)`

`g_p=2* g_e`

`g_p=2* 32\ ft/s^2`

`g_p=64\ ft/s^2`

So, the acceleration on the planet is 64 feet per second square. Hence, this is the required solution.