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The speed of cars on a stretch of road is normally distributed with an average 51 miles per hour with a standard deviation of 5.9 miles per hour. What is the probability that a randomly selected car is violating the speed limit of 50 miles per hour?

0.43

0.50

0.51

0.57

1 Answer

2 votes

Answer: 0.57

Explanation:

Given : The speed of cars on a stretch of road is normally distributed .

Population Mean =
\mu=51\text{ miles per hour}

Standard deviation :
\sigma= 5.9\text{ miles per hour}

Let x be the random variable that represents the speed of cars on a stretch of road .

z-score :
z=(x-\mu)/(\sigma)

For x= 50.


z=(50-51)/(5.9)\approx-0.17

By using the standard normal distribution table ,

The probability that a randomly selected car is violating the speed limit of 50 miles per hour :-


P(x>50)=1-P(x\leq50)=1-P(z\leq-0.17)\\\\=1- 0.4325051=0.5674949\approx0.57\\

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